Creating N nested for-loops

Question

Is there a way to create for-loops of a form

for(int i = 0; i < 9; ++i) {
    for(int j = 0; j < 9; ++i) {
    //...
        for(int k = 0; k < 9; +         


        

Answer 1

I'm going to take the OP at face value on the example code that was given, and assume what's being asked for is a solution that counts through an arbitrary base-10 number. (I'm basing this on the comment "Ideally I'm trying to figure out a way to loop through seperate elements of a vector of digits to create each possible number".

This solution has a loop that counts through a vector of digits in base 10, and passes each successive value into a helper function (doThingWithNumber). For testing purposes I had this helper simply print out the number.

#include 

using namespace std;

void doThingWithNumber(const int* digits, int numDigits)
{
    int i;
    for (i = numDigits-1; i>=0; i--)
        cout << digits[i];
    cout << endl;
}

void loopOverAllNumbers(int numDigits)
{
    int* digits = new int [numDigits];
    int i;
    for (i = 0; i< numDigits; i++) 
        digits[i] = 0;

    int maxDigit = 0;
    while (maxDigit < numDigits) {
        doThingWithNumber(digits, numDigits);
        for (i = 0; i < numDigits; i++) {
            digits[i]++;
            if (digits[i] < 10)
                break;
            digits[i] = 0;
        }
        if (i > maxDigit)
            maxDigit = i;
    }
}

int main()
{
    loopOverAllNumbers(3);
    return 0;
}