Python: find a list within members of another list(in order)

Question

If I have this:

a=\'abcdefghij\'
b=\'de\'

Then this finds b in a:

b in a => True

Is there a way of doi

Answer 1

Use the lists' string representation and remove the square braces. :)

def is_sublist(a, b):
    return str(a)[1:-1] in str(b)

EDIT: Right, there are false positives ... e.g. is_sublist([1], [11]). Crappy answer. :)