Python: find a list within members of another list(in order)

Question

If I have this:

a=\'abcdefghij\'
b=\'de\'

Then this finds b in a:

b in a => True

Is there a way of doi

Answer 1

This should work with whatever couple of lists, preserving the order. Is checking if b is a sub list of a

def is_sublist(b,a): 

    if len(b) > len(a):
        return False    

    if a == b:
        return True    

    i = 0
    while i <= len(a) - len(b):
        if a[i] == b[0]:
            flag = True
            j = 1
            while i+j < len(a) and j < len(b):
                if a[i+j] != b[j]:
                    flag = False
                j += 1
            if flag:
                return True
        i += 1
    return False