I have a data.table:
set.seed(1)
data <- data.table(time = c(1:3, 1:4),
groups = c(rep(c(\"b\", \"a\"), c(3, 4))),
v
Using package dplyr
:
library(dplyr)
data <-
data %>%
group_by(groups) %>%
mutate(lag.value = dplyr::lag(value, n = 1, default = NA))
gives
> data
Source: local data table [7 x 4]
Groups: groups
time groups value lag.value
1 1 a 0.07614866 NA
2 2 a -0.02784712 0.07614866
3 3 a 1.88612245 -0.02784712
4 1 b 0.26526825 NA
5 2 b 1.23820506 0.26526825
6 3 b 0.09276648 1.23820506
7 4 b -0.09253594 0.09276648
As noted by @BrianD, this implicitly assumes that value is sorted by group already. If not, either sort it by group, or use the order_by
argument in lag
. Also note that due to an existing issue with some versions of dplyr, for safety, arguments and the namespace should be explicitly given.