C++ virtual function table memory cost

Question

Consider:

class A
{
    public:
        virtual void update() = 0;
}

class B : public A
{
    public:
        void update() { /* stuff goes in here... */ }
         


        

Answer 1

If you really want to save memory of virtual table pointer in each object then you can implement code in C-style...

E.g.

struct Point2D {
int x,y;
};

struct Point3D {
int x,y,z;
};

void Draw2D(void *pThis)
{
  Point2D *p = (Point2D *) pThis;
  //do something 
}

void Draw3D(void *pThis)
{
  Point3D *p = (Point3D *) pThis;
 //do something 
}

int main()
{

    typedef void (*pDrawFunct[2])(void *);

     pDrawFunct p;
     Point2D pt2D;
     Point3D pt3D;   

     p[0] = &Draw2D;
     p[1] = &Draw3D;    

     p[0](&pt2D); //it will call Draw2D function
     p[1](&pt3D); //it will call Draw3D function
     return 0; 
}