How to get device make and model on iOS?

Question

I was wondering if it\'s possible to determine what kind of iPhone (for example) the currentdevice is? I know it\'s possible to get the model through
NSString

Answer 1

If you have a plist of devices (eg maintained by @Tib above in https://stackoverflow.com/a/17655825/849616) to handle it if Swift 3 you'd use:

extension UIDevice {
    /// Fetches the information about the name of the device.
    ///
    /// - Returns: Should return meaningful device name, if not found will return device system code.
    public static func modelName() -> String {
        let physicalName = deviceSystemCode()
        if let deviceTypes = deviceTypes(), let modelName = deviceTypes[physicalName] as? String {
            return modelName
        }
        return physicalName
    }
}

private extension UIDevice {
    /// Fetches from system the code of the device
    static func deviceSystemCode() -> String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
        return identifier
    }

    /// Fetches the plist entries from plist maintained in https://stackoverflow.com/a/17655825/849616
    ///
    /// - Returns: A dictionary with pairs of deviceSystemCode <-> meaningfulDeviceName.
    static func deviceTypes() -> NSDictionary? {
        if let fileUrl = Bundle.main.url(forResource: "your plist name", withExtension: "plist"),
            let configurationDictionary = NSDictionary(contentsOf: fileUrl) {
            return configurationDictionary
        }
        return nil
    }
}

Later you can call it using UIDevice.modelName().

Additional credits go to @Tib (for plist), @Aniruddh Joshi (for deviceSystemCode() function).