How to get device make and model on iOS?

Question

I was wondering if it\'s possible to determine what kind of iPhone (for example) the currentdevice is? I know it\'s possible to get the model through
NSString

Answer 1

This solution works for both physical devices and iOS simulator in a way that simulator returns the same model as physical device would return for a model e.g. "iPhone10,6" for iPhone X (GSM) rather than "x86_64".

Definition - Swift 4:

import UIKit

extension UIDevice {
    var modelName: String {
        var systemInfo = utsname()
        uname(&systemInfo)
        let machineMirror = Mirror(reflecting: systemInfo.machine)
        let identifier = machineMirror.children.reduce("") { identifier, element in
            guard let value = element.value as? Int8, value != 0 else { return identifier }
            return identifier + String(UnicodeScalar(UInt8(value)))
        }
        if let value = ProcessInfo.processInfo.environment["SIMULATOR_MODEL_IDENTIFIER"] {
            return value
        } else {
            return identifier
        }
    }
}

Usage:

print(UIDevice.current.modelName)