Reading lines in a file and avoiding lines with # with Bash

Question

I tried this:

file=\"myfile\"
while read -r line
do
    [[ $line = \\#* ]] && continue
    \"address=\\$line\\127.0.0.1\"
done < \"$file\"
         


        

Answer 1

It has 3 parts. Please read each to understand clearly

1. To remove # line ----- awk -F'#' '{print $1}' t.txt
2. To remove a blank line created by # ---- awk 'NF > 0'
3. To print in required format. ------awk '{print "address=/"$0"/127.0.0.1"}'

So Total Script Needed is,

**awk -F'#' '{print $1}' t.txt | awk 'NF > 0' | awk '{print "address=/"$0"/127.0.0.1"}'**

Output :

address=/domain1.com/127.0.0.1
address=/domain2.com/127.0.0.1
address=/domain3.com/127.0.0.1
address=/domain5.com/127.0.0.1