Braces around string literal in char array declaration valid? (e.g. char s[] = {“Hello World”})

Question

By accident I found that the line char s[] = {\"Hello World\"}; is properly compiled and seems to be treated the same as char s[] = \"Hello World\";

Answer 1

[...] In fact if I change it to char *s[] = {"Hello World"}; the compiler accepts it as well, as expected

The compiler accepets it,because actually, you're making an array 2D of undefined size elements,where you stored one element only,the "Hello World" string. Something like this:

char* s[] = {"Hello world", "foo", "baa" ...};

You can't omit the bracets in this case.