Get the first item from an iterable that matches a condition

Question

I would like to get the first item from a list matching a condition. It\'s important that the resulting method not process the entire list, which could be quite large. For e

Answer 1

Damn Exceptions!

I love this answer. However, since next() raise a StopIteration exception when there are no items, i would use the following snippet to avoid an exception:

a = []
item = next((x for x in a), None)

---

For example,

a = []
item = next(x for x in a)

Will raise a StopIteration exception;

Traceback (most recent call last):
  File "", line 1, in 
StopIteration