jquery ajax load certain div

后端 未结 3 647
耶瑟儿~
耶瑟儿~ 2020-12-03 05:52

my question is very simple how can I retrieve certain div with jquery ajax comand

$.ajax({
      url: \"test.html\",
      success: function(){
           $         


        
3条回答
  •  借酒劲吻你
    2020-12-03 06:26

    Here is an example that I use on my site for the navigation.

     
    

    For the javascript you can try this.

    var hash = window.location.hash.substr(1);
    var hash2 = window.location.hash.substr(1);
    
    // Menu items to lower main content
    var href = $('.ajax_nav').each(function(){
        var href = $(this).attr('href');
        if(hash==href.substr(0,href.length-4)){
            var toLoad = hash+'.html #ajax_content';
            $('#ajax_content').load(toLoad)
        }                                           
    });
    
    // For inner overlay of featured content. 
    var href2 = $('.feat_item_link').each(function(){
        var href2 = $(this).attr('href');
        if(hash2==href2.substr(0,href.length-4)){
            var toLoadFeatured = hash2+'.html #ajax_featured_content';
            $('#ajax_featured_content').load(toLoadFeatured);
        }                                           
    });
    
    // For Bottom Navigation
    $('#nav li a').click(function(){
    
        var toLoad = $(this).attr('href')+' #ajax_content';
        $('#content').hide('fast',loadContent);
        $('#load').remove();
        $('#wrapper').append('LOADING...');
        $('#load').fadeIn('normal');
    
        window.location.hash = $(this).attr('href').substr(0,$(this).attr('href'));
        function loadContent() {
            $('#content').delay(1000).load(toLoad,'',showNewContent());
        }
        function showNewContent() {
            $('#content').show('normal',hideLoader());
        }
        function hideLoader() {
            $('#load').delay(1000).fadeOut('normal');
        }
        return false;
    });
    

    The id of #load simply uses an animated gif in the CSS.

    Place the javascript in the $(document).ready() and you should be all set.

提交回复
热议问题