int *array = new int[n]; what is this function actually doing?

Question

I am confused about how to create a dynamic defined array:

 int *array = new int[n];

I have no idea what this is doing. I can tell it\'s c

Answer 1

The new operator is allocating space for a block of n integers and assigning the memory address of that block to the int* variable array.

The general form of new as it applies to one-dimensional arrays appears as follows:

array_var = new Type[desired_size];