int *array = new int[n]; what is this function actually doing?

Question

I am confused about how to create a dynamic defined array:

 int *array = new int[n];

I have no idea what this is doing. I can tell it\'s c

Answer 1

In C/C++, pointers and arrays are (almost) equivalent. int *a; a[0]; will return *a, and a[1]; will return *(a + 1)

But array can't change the pointer it points to while pointer can.

new int[n] will allocate some spaces for the "array"