int *array = new int[n]; what is this function actually doing?

Question

I am confused about how to create a dynamic defined array:

 int *array = new int[n];

I have no idea what this is doing. I can tell it\'s c

Answer 1

It allocates that much space according to the value of n and pointer will point to the array i.e the 1st element of array

int *array = new int[n];