int *array = new int[n]; what is this function actually doing?

Question

I am confused about how to create a dynamic defined array:

 int *array = new int[n];

I have no idea what this is doing. I can tell it\'s c

Answer 1

It allocates space on the heap equal to an integer array of size N, and returns a pointer to it, which is assigned to int* type pointer called "array"