int *array = new int[n]; what is this function actually doing?

Question

I am confused about how to create a dynamic defined array:

 int *array = new int[n];

I have no idea what this is doing. I can tell it\'s c

Answer 1

The statement basically does the following:

1. Creates a integer array of 'n' elements
2. Allocates the memory in HEAP memory of the process as you are using new operator to create the pointer
3. Returns a valid address (if the memory allocation for the required size if available at the point of execution of this statement)