In Node.js, how do I “include” functions from my other files?

Question

Let\'s say I have a file called app.js. Pretty simple:

var express = require(\'express\');
var app = express.createServer();
app.set(\'views\', __dirname + \         


        

Answer 1

Like you are having a file abc.txt and many more?

Create 2 files: fileread.js and fetchingfile.js, then in fileread.js write this code:

function fileread(filename) {
    var contents= fs.readFileSync(filename);
        return contents;
    }

    var fs = require("fs");  // file system

    //var data = fileread("abc.txt");
    module.exports.fileread = fileread;
    //data.say();
    //console.log(data.toString());
}

In fetchingfile.js write this code:

function myerror(){
    console.log("Hey need some help");
    console.log("type file=abc.txt");
}

var ags = require("minimist")(process.argv.slice(2), { string: "file" });
if(ags.help || !ags.file) {
    myerror();
    process.exit(1);
}
var hello = require("./fileread.js");
var data = hello.fileread(ags.file);  // importing module here 
console.log(data.toString());

Now, in a terminal: $ node fetchingfile.js --file=abc.txt

You are passing the file name as an argument, moreover include all files in readfile.js instead of passing it.

Thanks