String.split() *not* on regular expression?

Question

Since String.split() works with regular expressions, this snippet:

String s = \"str?str?argh\";
s.split(\"r?\");

... yields: <

Answer 1

Using directly the Pattern class, is possible to define the expression as LITERAL, and in that case, the expression will be evaluated as is (not regex expression).

Pattern.compile(, Pattern.LITERAL).split();

example:

String[] result = Pattern.compile("r?", Pattern.LITERAL).split("str?str?argh");

will result:

[st, st, argh]