Comparison operation on unsigned and signed integers

Question

See this code snippet

int main()
{ 
 unsigned int a = 1000;
 int b = -1;
 if (a>b) printf(\"A is BIG! %d\\n\", a-b);
 else printf(\"a is SMALL! %d\\n\", a         


        

Answer 1

You are doing unsigned comparison, i.e. comparing 1000 to 2^32 - 1.

The output is signed because of %d in printf.

N.B. sometimes the behavior when you mix signed and unsigned operands is compiler-specific. I think it's best to avoid them and do casts when in doubt.