SQL 'LIKE' query using '%' where the search criteria contains '%'

Question

I have an SQL query as below.

Select * from table 
where name like \'%\' + search_criteria + \'%\' 

If search_criteria = \'abc\', it will r

Answer 1

Use an escape clause:

select *
  from (select '123abc456' AS result from dual
        union all
        select '123abc%456' AS result from dual
       )
  WHERE result LIKE '%abc\%%' escape '\'

Result

123abc%456

You can set your escape character to whatever you want. In this case, the default '\'. The escaped '\%' becomes a literal, the second '%' is not escaped, so again wild card.

See List of special characters for SQL LIKE clause