SQL 'LIKE' query using '%' where the search criteria contains '%'

Question

I have an SQL query as below.

Select * from table 
where name like \'%\' + search_criteria + \'%\' 

If search_criteria = \'abc\', it will r

Answer 1

If you want a % symbol in search_criteria to be treated as a literal character rather than as a wildcard, escape it to [%]

... where name like '%' + replace(search_criteria, '%', '[%]') + '%'