Synchronous delay in code execution

Question

I have a code which needs to be executed after some delay say 5000 ms.Currently I am using setTimeout but it is asynchronous and i want the execution to wait for its return.

Answer 1

Synchronous wait (only for testing!):

const syncWait = ms => {
    const end = Date.now() + ms
    while (Date.now() < end) continue
}

Usage:

console.log('one')
syncWait(5000)
console.log('two')

Asynchronous wait:

const asyncWait = ms => new Promise(resolve => setTimeout(resolve, ms))

Usage:

(async () => {
    console.log('one')
    await asyncWait(5000)
    console.log('two')
})()

Alternative (asynchronous):

const delayedCall = (array, ms) =>
    array.forEach((func, index) => setTimeout(func, index * ms))

Usage:

delayedCall([
    () => console.log('one'),
    () => console.log('two'),
    () => console.log('three'),
], 5000)