I have been asked to test a library provided by a 3rd party. The library is known to be accurate to n significant figures. Any less-significant errors can safely be
This is a fairly common issue with floating point numbers. I solve it based on the discussion in Section 1.5 of Demmel[1]. (1) Calculate the roundoff error. (2) Check that the roundoff error is less than some epsilon. I haven't used python in some time and only have version 2.4.3, but I'll try to get this correct.
Step 1. Roundoff error
def roundoff_error(exact, approximate):
return abs(approximate/exact - 1.0)
Step 2. Floating point equality
def float_equal(float1, float2, epsilon=2.0e-9):
return (roundoff_error(float1, float2) < epsilon)
There are a couple obvious deficiencies with this code.
Revision 1.
def roundoff_error(exact, approximate):
if (exact == 0.0 or approximate == 0.0):
return abs(exact + approximate)
else:
return abs(approximate/exact - 1.0)
def float_equal(float1, float2, epsilon=2.0e-9):
if not isinstance(float1,float):
raise TypeError,"First argument is not a float."
elif not isinstance(float2,float):
raise TypeError,"Second argument is not a float."
else:
return (roundoff_error(float1, float2) < epsilon)
That's a little better. If either the exact or the approximate value is zero, than the error is equal to the value of the other. If something besides a floating point value is provided, a TypeError is raised.
At this point, the only difficult thing is setting the correct value for epsilon. I noticed in the documentation for version 2.6.1 that there is an epsilon attribute in sys.float_info, so I would use twice that value as the default epsilon. But the correct value depends on both your application and your algorithm.
[1] James W. Demmel, Applied Numerical Linear Algebra, SIAM, 1997.