The behaviour of floating point division by zero

Question

Consider

#include 
int main()
{
    double a = 1.0 / 0;
    double b = -1.0 / 0;
    double c = 0.0 / 0;
    std::cout << a << b          


        

Answer 1

As to the submitter's question 'Who's correct?', it is perfectly OK to say that both answers are correct. The fact that the C standard describes the behavior as 'undefined' DOES NOT dictate what the underlying hardware actually does; it merely means that if you want your program to be meaningful according to the standard you -may not assume- that the hardware actually implements that operation. But if you happen to be running on hardware that implements the IEEE standard, you will find the operation is in fact implemented, with the results as stipulated by the IEEE standard.