No Persistence provider for EntityManager named

Question

I have my persistence.xml with the same name using TopLink under the META-INF directory. Then, I have my code calling it with:

Answer 1

Hibernate 5.2.5
Jar Files Required in the class path. This is within a required folder of Hibernate 5.2.5 Final release. It can be downloaded from http://hibernate.org/orm/downloads/

1. antlr-2.7.7
2. cdi-api-1.1
3. classmate-1.3.0
4. dom4j-1.6.1
5. el-api-2.2
6. geronimo-jta_1.1_spec-1.1.1
7. hibernate-commons-annotation-5.0.1.Final
8. hibernate-core-5.2.5.Final
9. hibernate-jpa-2.1-api-1.0.0.Final
10. jandex-2.0.3.Final
11. javassist-3.20.0-GA
12. javax.inject-1
13. jboss-interceptor-api_1.1_spec-1.0.0.Beta1
14. jboss-logging-3.3.0.Final
15. jsr250-api-1.0

Create an xml file "persistence.xml" in

YourProject/src/META-INF/persistence.xml

persistence.xml

    org.pramod.data.object.UserDetail
    true
    
        
        
        
        
        
        
        
        

        

        
    

1. please note down the information mentioned in the < persistance > tag and version should be 2.1.
2. please note the name < persistance-unit > tag, name is mentioned as "sample". This name needs to be used exactly same while loading your

EntityManagerFactor = Persistance.createEntityManagerFactory("sample");. "sample" can be changed as per your naming convention.

Now create a Entity class. with name as per my example UserDetail, in the package org.pramod.data.object

UserDetail.java

package org.pramod.data.object;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name = "user_detail")
public class UserDetail {
    @Id
    @Column(name="user_id")
    private int id;
    @Column(name="user_name")
    private String userName;

    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getUserName() {
        return userName;
    }
    public void setUserName(String userName) {
        this.userName = userName;
    }   
    @Override
    public String toString() {
       return "UserDetail [id=" + id + ", userName=" + userName + "]";
    }
}

Now create a class with main method.

HibernateTest.java

package org.pramod.hibernate;

import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;
import org.pramod.data.object.UserDetail;

public class HibernateTest {
    private static EntityManagerFactory entityManagerFactory;

    public static void main(String[] args)  {
        UserDetail user = new UserDetail();
        user.setId(1);
        user.setUserName("Pramod Sharma");

        try {
            entityManagerFactory = Persistence.createEntityManagerFactory("sample");
            EntityManager entityManager = entityManagerFactory.createEntityManager();
            entityManager.getTransaction().begin();
            entityManager.persist( user );
            entityManager.getTransaction().commit();
            System.out.println("successfull");
            entityManager.close();
        } catch (Exception e) {
            e.printStackTrace();
        }

    }

}

Output will be

UserDetail [id=1, userName=Pramod Sharma]
Hibernate: drop table if exists user_details
Hibernate: create table user_details (user_id integer not null, user_name varchar(255), primary key (user_id))
Hibernate: insert into user_details (user_name, user_id) values (?, ?)
successfull