select columns based on columns names containing a specific string in pandas

Question

I created a dataframe using the following:

df = pd.DataFrame(np.random.rand(10, 3), columns=[\'alp1\', \'alp2\', \'bet1\'])

I\'d like to ge

Answer 1

option 1
Full numpy + pd.DataFrame

m = np.core.defchararray.find(df.columns.values.astype(str), 'alp') >= 0
pd.DataFrame(df.values[:, m], df.index, df.columns[m])

       alp1      alp2
0  0.819189  0.356867
1  0.900406  0.968947
2  0.201382  0.658768
3  0.700727  0.946509
4  0.176423  0.290426
5  0.132773  0.378251
6  0.749374  0.983251
7  0.768689  0.415869
8  0.292140  0.457596
9  0.214937  0.976780

option 2
numpy + loc

m = np.core.defchararray.find(df.columns.values.astype(str), 'alp') >= 0
df.loc[:, m]

       alp1      alp2
0  0.819189  0.356867
1  0.900406  0.968947
2  0.201382  0.658768
3  0.700727  0.946509
4  0.176423  0.290426
5  0.132773  0.378251
6  0.749374  0.983251
7  0.768689  0.415869
8  0.292140  0.457596
9  0.214937  0.976780

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timing
numpy is faster