I want to convert (\"USERID=XYZ\" \"USERPWD=123\") to \"USERID=XYZ&USERPWD=123\". I tried
(apply #\'concatenate \'string \'(\"
Assuming a list of strings and a single character delimiter, the following should work efficiently for frequent invocation on short lists:
(defun join (list &optional (delimiter #\&))
(with-output-to-string (stream)
(join-to-stream stream list delimiter)))
(defun join-to-stream (stream list &optional (delimiter #\&))
(destructuring-bind (&optional first &rest rest) list
(when first
(write-string first stream)
(when rest
(write-char delimiter stream)
(join-to-stream stream rest delimiter)))))