Regex for extracting filename from path

Question

I need to extract just the filename (no file extension) from the following path....

\\\\my-local-server\\path\\to\\this_file may_contain-any&character.pdf<

Answer 1

TEST ^(.*[\\\/])?(.*?)(\.[^.]*?|)$

example:

/^(.*[\\\/])?(.*?)(\.[^.]*?|)$/.exec("C:\\folder1\\folder2\\foo.ext1.ext")

result:

0: "C:\folder1\folder2\foo.ext1.ext"
1: "C:\folder1\folder2\"
2: "foo.ext1"
3: ".ext"

the $1 capture group is the folder
the $2 capture group is the name without extension
the $3 capture group is the extension (only the last)

works for:

• C:\folder1\folder2\foo.ext
• C:\folder1\folder2\foo.ext1.ext
• C:\folder1\folder2\name-without extension
• only name
• name.ext
• C:\folder1\folder2\foo.ext
• /folder1/folder2/foo.ext
• C:\folder1\folder2\foo
• C:\folder1\folder2\
• C:\special&chars\folder2\f [oo].ext1.e-x-t