NSNumberFormatter and 'th' 'st' 'nd' 'rd' (ordinal) number endings

Question

Is there a way to use NSNumberFormatter to get the \'th\' \'st\' \'nd\' \'rd\' number endings?

EDIT:

Looks like it does not exist. Here\'s what I\'m using.

Answer 1

- (NSString *) formatOrdinalNumber:(NSInteger )number{
    NSString *result = nil;
    //0 remains just 0
    if (number == 0) {
        result = @"0";
    }

    //test for number between 3 and 21 as they follow a
    //slightly different rule and all end with th
    else if (number > 3 && number < 21)
    {
        result = [NSString stringWithFormat:@"%ld th",(long)number];
    }
    else {
        //return the last digit of the number e.g. 102 is 2
        NSInteger lastdigit = number % 10;
        switch (lastdigit)
        {
            case 1: result = [NSString stringWithFormat:@"%ld st",(long)number]; break;
            case 2: result = [NSString stringWithFormat:@"%ld nd",(long)number]; break;
            case 3: result = [NSString stringWithFormat:@"%ld rd",(long)number]; break;
            default: result = [NSString stringWithFormat:@"%ld th",(long)number];
        }
    }
    return result;
}