NSNumberFormatter and 'th' 'st' 'nd' 'rd' (ordinal) number endings

Question

Is there a way to use NSNumberFormatter to get the \'th\' \'st\' \'nd\' \'rd\' number endings?

EDIT:

Looks like it does not exist. Here\'s what I\'m using.

Answer 1

A clean Swift version (for English only):

func ordinal(number: Int) -> String {
    if (11...13).contains(number % 100) {
        return "\(number)th"
    }
    switch number % 10 {
        case 1: return "\(number)st"
        case 2: return "\(number)nd"
        case 3: return "\(number)rd"
        default: return "\(number)th"
    }
}

Can be done as an extension for Int:

extension Int {

    func ordinal() -> String {
        return "\(self)\(ordinalSuffix())"
    }

    func ordinalSuffix() -> String {
        if (11...13).contains(self % 100) {
            return "th"
        }
        switch self % 10 {
            case 1: return "st"
            case 2: return "nd"
            case 3: return "rd"
            default: return "th"
        }
    }

}