Swift: shortcut unwrapping of array of optionals

Question

Assume we have an array of optionals defined:

var arrayOfOptionals: [String?] = [\"Seems\", \"like\", \"an\", nil, \"of\", \"optionals\"]

I

Answer 1

How about:

import Foundation

var test: [String!] = ["this","is","a",nil,"test"]
for string in test {
    if string != nil {
        print(string)
    }
}

Output is thisisatest.

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In your case use [String!], if I understood you correctly.