What is the difference between the dot (.) operator and -> in C++? [duplicate]

Answer 1

Note that the -> operator cannot be used for certain things, for instance, accessing operator[].

#include 

int main()
{
   std::vector iVec;
   iVec.push_back(42);
   std::vector* iVecPtr = &iVec;

   //int i = iVecPtr->[0]; // Does not compile
   int i = (*iVecPtr)[0]; // Compiles.
}