How to wait in bash for several subprocesses to finish and return exit code !=0 when any subprocess ends with code !=0?

Question

How to wait in a bash script for several subprocesses spawned from that script to finish and return exit code !=0 when any of the subprocesses ends with code !=0 ?

S

Answer 1

set -e
fail () {
    touch .failure
}
expect () {
    wait
    if [ -f .failure ]; then
        rm -f .failure
        exit 1
    fi
}

sleep 2 || fail &
sleep 2 && false || fail &
sleep 2 || fail
expect

The set -e at top makes your script stop on failure.

expect will return 1 if any subjob failed.