Python functions with multiple parameter brackets

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走了就别回头了
走了就别回头了 2020-12-02 22:54

I\'ve been having trouble understanding what h(a)(b) means. I\'d never seen one of those before yesterday, and I couldn\'t declare a function this way:

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  •  忘掉有多难
    2020-12-02 23:19

    Functions with multiple parameter brackets don't exist, as you saw when you tried to define one. There are, however, functions which return (other) functions:

    def func(a):
        def func2(b):
            return a + b
        return func2
    

    Now when you call func() it returns the inner func2 function:

    >>> func2 = func(1)  # You don't have to call it func2 here
    >>> func2(2)
    3
    

    But if you don't need the inner function later on, then there's no need to save it into a variable and you can just call them one after the other:

    >>> func(1)(2)   # func(1) returns func2 which is then called with (2)
    3
    

    This is a very common idiom when defining decorators that take arguments.


    Notice that calling func() always creates a new inner function, even though they're all named func2 inside of the definition of our func:

    >>> f1 = func(1)
    >>> f2 = func(1)
    >>> f1(1), f2(1)
    (2, 2)
    >>> f1 is f2
    False
    

    And, finally, what's the difference between f(a, b)and f(a)(b)?

    It should be clear now that you know what f(a)(b) does, but to summarize:

    • f(a, b) calls f with two parameters a and b
    • f(a)(b) calls f with one parameter a, which then returns another function, which is then called with one parameter b

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