Shell run/execute php script with parameters

Question

I need to execute a php file with parameters through shell.

here is how I would run the php file:

php -q htdocs/file.php

Answer 1

If you are using it from a PHP file then you can use popen() and do something like this:

$part = $show_name; //or whatever you want with spaces

$handle = popen("php -q nah.php -p=". escapeshellarg($part) . " 2>&1", "r");

This uses the escapeshellarg() function in order to wrap the $part variable in quotes (and escape any quotes inside it), so that it can be used as a shell argument safely.