Shell run/execute php script with parameters

Question

I need to execute a php file with parameters through shell.

here is how I would run the php file:

php -q htdocs/file.php

Answer 1

If you have webserver (not only just php interpreter installed, but LAMP/LNMP/etc) - just try this

wget -O - -q -t 1 "http://mysite.com/file.php?show=show_name" >/dev/null 2>&1

where:

• « -O - » — (Letter "O", not zero!) redirect "downloaded html" to stdout
• « >/dev/null 2>&1 » — redirect stdout & stderr output to nowhere
• « -q » — quiet wget run
• « -t 1 » — just 1 try to connect (not like default 20)

In PHP's "exec" it'll be smth like this:

function exec_local_url($url) {
  exec('/usr/bin/wget -O - -q -t 1 "http://'. $_SERVER['HTTP_HOST'] .'/'
    . addslashes($url) . '" >/dev/null 2>&1'
  );
}

// ...

exec_local_url("file.php?show=show_name");
exec_local_url("myframework/seo-readable/show/show_name");

So, you don't need to change your scripts to handle argc/argv, and may use $_GET as usually do.

If you want jobs runned in background - see for ex. Unix/Windows, Setup background process? from php code

I use approach with wget in my cron jobs; hope it helps.