How to sort a list of strings numerically?

Question

I know that this sounds trivial but I did not realize that the sort() function of Python was weird. I have a list of \"numbers\" that are actually in string for

Answer 1

may be not the best python, but for string lists like ['1','1.0','2.0','2', '1.1', '1.10', '1.11', '1.2','7','3','5']with the expected target ['1', '1.0', '1.1', '1.2', '1.10', '1.11', '2', '2.0', '3', '5', '7'] helped me...

unsortedList = ['1','1.0','2.0','2', '1.1', '1.10', '1.11', '1.2','7','3','5']
sortedList = []
sortDict = {}
sortVal = []
#set zero correct (integer): examp: 1.000 will be 1 and breaks the order
zero = "000"
for i in sorted(unsortedList):
  x = i.split(".")
  if x[0] in sortDict:
    if len(x) > 1:
        sortVal.append(x[1])
    else:
        sortVal.append(zero)
    sortDict[x[0]] = sorted(sortVal, key = int)
  else:
    sortVal = []
    if len(x) > 1:
        sortVal.append(x[1])
    else:
        sortVal.append(zero)
    sortDict[x[0]] = sortVal
for key in sortDict:
  for val in sortDict[key]:
    if val == zero:
       sortedList.append(str(key))
    else:
       sortedList.append(str(key) + "." + str(val))
print(sortedList)