How to create a django ViewFlow process programmatically

Question

Synopsis

I\'m developing a web application to learn Django (python 3.4 & Django 1.6.10). The web app has complex and often updated workflows. I decided

Answer 1

to start manually:

from viewflow import flow
from viewflow.base import this, Flow
from .models import CIE
from viewflow import frontend
from django.utils.decorators import method_decorator

@frontend.register
class CIE(Flow):
    process_class = CIE
    start = flow.StartFunction(this.create_flow).Next(this.end)
    end = flow.End()

    @method_decorator(flow.flow_start_func)
    def create_flow(self, activation):
        activation.prepare()
        activation.done()
        return activation

after that expose rpc:

from modernrpc.core import rpc_method
from flow.flows import CIE

    @rpc_method
    def start():
        CIE.start.run()