Python: How to pass arguments to the __code__ of a function?

Question

The following works:

def spam():
    print \"spam\"
exec(spam.__code__)

spam

But what if spam

Answer 1

I don't think you can pass arguments to either exec or eval, so that they are passed to the code object.

You could resort to the string version of exec/eval, e.g. exec("spam(3)").

You could create another code object that binds the argument, and then exec this:

def spam_with_eggs():
   return spam(3)
exec(spam_with_eggs.__code__)

(I thought you could also achieve this with functools.partial, but didn't get it to work).

EDIT:

After reading your additional explanations I thought of ways to re-establish a proper function from the code object. This simple approach worked for me (in python2.5):

def bar():pass
bar.func_code = spam.func_code
bar(3)  # yields "spam and 3"