Python: How to pass arguments to the __code__ of a function?

Question

The following works:

def spam():
    print \"spam\"
exec(spam.__code__)

spam

But what if spam

Answer 1

My method, I thing it`s more beautiful

def f(x):
    print(x, x+1)

g = type(f)(f.__code__, globals(), "optional_name")

g(3)