Python: How to pass arguments to the __code__ of a function?

Question

The following works:

def spam():
    print \"spam\"
exec(spam.__code__)

spam

But what if spam

Answer 1

A code object is part of a function, so several answers above suggest creating a dummy function and replacing its __code__ with your codeObject. Here's another way that avoids making and throwing away a new __code__:

import new
newFunction = new.function(codeObject, globals())

(Tested in Python 2.7, where spam.__code__ is named spam.func_code.)