Python: How to pass arguments to the __code__ of a function?

Question

The following works:

def spam():
    print \"spam\"
exec(spam.__code__)

spam

But what if spam

Answer 1

I think there are probably some design considerations in your larger application that could make you not care about this problem, like perhaps having some collection of 'known good and valid' functions distributed as a module that the executing agents know about or something.

That said, one hacky solution would be:

>>> def spam(eggs):
...     print "spam and %s" % eggs
...     
... 
>>> spam('bacon')
spam and bacon
>>> def util():
...     pass
...     
... 
>>> util.__code__ = spam.__code__
>>> util('bacon')
spam and bacon
>>>