How to check if a number is a power of 2

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爱一瞬间的悲伤
爱一瞬间的悲伤 2020-11-22 03:30

Today I needed a simple algorithm for checking if a number is a power of 2.

The algorithm needs to be:

  1. Simple
  2. Correct for any ulong
25条回答
  •  我在风中等你
    2020-11-22 03:53

    There's a simple trick for this problem:

    bool IsPowerOfTwo(ulong x)
    {
        return (x & (x - 1)) == 0;
    }
    

    Note, this function will report true for 0, which is not a power of 2. If you want to exclude that, here's how:

    bool IsPowerOfTwo(ulong x)
    {
        return (x != 0) && ((x & (x - 1)) == 0);
    }
    

    Explanation

    First and foremost the bitwise binary & operator from MSDN definition:

    Binary & operators are predefined for the integral types and bool. For integral types, & computes the logical bitwise AND of its operands. For bool operands, & computes the logical AND of its operands; that is, the result is true if and only if both its operands are true.

    Now let's take a look at how this all plays out:

    The function returns boolean (true / false) and accepts one incoming parameter of type unsigned long (x, in this case). Let us for the sake of simplicity assume that someone has passed the value 4 and called the function like so:

    bool b = IsPowerOfTwo(4)
    

    Now we replace each occurrence of x with 4:

    return (4 != 0) && ((4 & (4-1)) == 0);
    

    Well we already know that 4 != 0 evals to true, so far so good. But what about:

    ((4 & (4-1)) == 0)
    

    This translates to this of course:

    ((4 & 3) == 0)
    

    But what exactly is 4&3?

    The binary representation of 4 is 100 and the binary representation of 3 is 011 (remember the & takes the binary representation of these numbers). So we have:

    100 = 4
    011 = 3
    

    Imagine these values being stacked up much like elementary addition. The & operator says that if both values are equal to 1 then the result is 1, otherwise it is 0. So 1 & 1 = 1, 1 & 0 = 0, 0 & 0 = 0, and 0 & 1 = 0. So we do the math:

    100
    011
    ----
    000
    

    The result is simply 0. So we go back and look at what our return statement now translates to:

    return (4 != 0) && ((4 & 3) == 0);
    

    Which translates now to:

    return true && (0 == 0);
    
    return true && true;
    

    We all know that true && true is simply true, and this shows that for our example, 4 is a power of 2.

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