How to get the caller class name inside a function of another class in python?

Question

My objective is to stimulate a sequence diagram of an application for this I need the information about a caller and callee class names at runtime. I can successfully retrie

Answer 1

Perhaps this is breaking some Python programming protocol, but if Bad is always going to check the class of the caller, why not pass the caller's __class__ to it as part of the call?

class A:

    def Apple(self):
        print "Hello"
        b=B()
        b.Bad(self.__class__)



class B:

    def Bad(self, cls):
        print "dude"
        print "Calling class:", cls


a=A()
a.Apple()

Result:

Hello
dude
Calling class: __main__.A

If this is bad form, and using inspect truly is the preferred way to get the caller's class, please explain why. I'm still learning about deeper Python concepts.