How to get the caller class name inside a function of another class in python?

Question

My objective is to stimulate a sequence diagram of an application for this I need the information about a caller and callee class names at runtime. I can successfully retrie

Answer 1

Using the answer from Python: How to retrieve class information from a 'frame' object?

I get something like this...

import inspect

def get_class_from_frame(fr):
  args, _, _, value_dict = inspect.getargvalues(fr)
  # we check the first parameter for the frame function is
  # named 'self'
  if len(args) and args[0] == 'self':
    # in that case, 'self' will be referenced in value_dict
    instance = value_dict.get('self', None)
    if instance:
      # return its class
      return getattr(instance, '__class__', None)
  # return None otherwise
  return None


class A(object):

    def Apple(self):
        print "Hello"
        b=B()
        b.Bad()

class B(object):

    def Bad(self):
        print"dude"
        frame = inspect.stack()[1][0]
        print get_class_from_frame(frame)


a=A()
a.Apple()

which gives me the following output:

Hello
dude

clearly this returns a reference to the class itself. If you want the name of the class, you can get that from the __name__ attribute.

Unfortunately, this won't work for class or static methods ...