PyQt sending parameter to slot when connecting to a signal

Question

I have a taskbar menu that when clicked is connected to a slot that gets the trigger event. Now the problem is that I want to know which menu item was clicked, but I don\'t

Answer 1

As already mentioned here you can use the lambda function to pass extra arguments to the method you want to execute.

In this example you can pass a string obj to the function AddControl() invoked when the button is pressed.

# Create the build button with its caption
self.build_button = QPushButton('&Build Greeting', self)
# Connect the button's clicked signal to AddControl
self.build_button.clicked.connect(lambda: self.AddControl('fooData'))
def AddControl(self, name):
    print name

Source: snip2code - Using Lambda Function To Pass Extra Argument in PyQt4