Initializing a Generic variable from a C# Type Variable

Question

I have a class that takes a Generic Type as part of its initialization.

public class AnimalContext
{
    public DoAnimalStuff()
    {
        //Anim         


        

Answer 1

What you mean by this part is possible:

new AnimalContext();

Obviously that exact syntax is wrong, and we'll get to that, but it is possible to construct an instance of a generic type at runtime when you don't know the type parameters until runtime.

What you mean by this part is not:

AnimalContext a_Context

That is, it is impossible to type a variable as a generic type if you don't know the type parameters at compile-time. Generics are compile-time constructs, and rely on having the type information available at compile-time. Given this, you lose all the benefits of generics if you don't know the types at compile-time.

Now, to construct an instance of a generic type at runtime when you don't know the type until runtime, you can say:

var type = typeof(AnimalContext<>).MakeGenericType(a.GetType());
var a_Context = Activator.CreateInstance(type);   

Note that the compile-time type of a_context is object. You will have to cast a_context to a type or interface that defines the methods you need to access. Often what you'll see people do here is have the generic type AnimalContext implement some interface (say IAnimalContext) or inherit from a non-generic base class (say AnimalContext) that defines the methods they need (so then you can cast a_context to the interface or the non-generic base class). Another alternative is to use dynamic. But again, keep in mind, you have none of the benefits of generic types in doing this.