See my code snippet below:
var list = [\'one\', \'two\', \'three\', \'four\'];
var str = \'one two, one three, one four, one\';
for ( var i = 0; i < list.
I did not like any of the answers above and came up with the below
function replaceLastOccurrenceInString(input, find, replaceWith) {
if (!input || !find || !replaceWith || !input.length || !find.length || !replaceWith.length) {
// returns input on invalid arguments
return input;
}
const lastIndex = input.lastIndexOf(find);
if (lastIndex < 0) {
return input;
}
return input.substr(0, lastIndex) + replaceWith + input.substr(lastIndex + find.length);
}
Usage:
const input = 'ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen twenty';
const find = 'teen';
const replaceWith = 'teenhundred';
const output = replaceLastOccurrenceInString(input, find, replaceWith);
console.log(output);
// output: ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteenhundred twenty
Hope that helps!