See my code snippet below:
var list = [\'one\', \'two\', \'three\', \'four\'];
var str = \'one two, one three, one four, one\';
for ( var i = 0; i < list.
Not as elegant as the regex answers above, but easier to follow for the not-as-savvy among us:
function removeLastInstance(badtext, str) {
var charpos = str.lastIndexOf(badtext);
if (charpos<0) return str;
ptone = str.substring(0,charpos);
pttwo = str.substring(charpos+(badtext.length));
return (ptone+pttwo);
}
I realize this is likely slower and more wasteful than the regex examples, but I think it might be helpful as an illustration of how string manipulations can be done. (It can also be condensed a bit, but again, I wanted each step to be clear.)