“A reference to a volatile field will not be treated as volatile” implications

Question

The following code

using System.Threading;

class Test
{
    volatile int counter = 0;
    public void Increment()
    {
        Interlocked.Increment(ref co         


        

Answer 1

Use this:

        #pragma warning disable 420
        //                       M
        //                      dM
        //                      MMr
        //                     4MMML                  .
        //                     MMMMM.                xf
        //     .              "MMMMM               .MM-
        //      Mh..          +MMMMMM            .MMMM
        //      .MMM.         .MMMMML.          MMMMMh
        //       )MMMh.        MMMMMM         MMMMMMM
        //        3MMMMx.     'MMMMMMf      xnMMMMMM"
        //        '*MMMMM      MMMMMM.     nMMMMMMP"
        //          *MMMMMx    "MMMMM\    .MMMMMMM=
        //           *MMMMMh   "MMMMM"   JMMMMMMP
        //             MMMMMM   3MMMM.  dMMMMMM            .
        //              MMMMMM  "MMMM  .MMMMM(        .nnMP"
        //  =..          *MMMMx  MMM"  dMMMM"    .nnMMMMM*
        //    "MMn...     'MMMMr 'MM   MMM"   .nMMMMMMM*"
        //     "4MMMMnn..   *MMM  MM  MMP"  .dMMMMMMM""
        //       ^MMMMMMMMx.  *ML "M .M*  .MMMMMM**"
        //          *PMMMMMMhn. *x > M  .MMMM**""
        //             ""**MMMMhx/.h/ .=*"
        //                      .3P"%....
        //                    nP"     "*MMnx
        if(Interlocked.CompareExchange(ref isLoaded, 1, 0) != 0)
            return;
        #pragma warning restore 420